x^2-19x+80=-80

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Solution for x^2-19x+80=-80 equation:


Simplifying
x2 + -19x + 80 = -80

Reorder the terms:
80 + -19x + x2 = -80

Solving
80 + -19x + x2 = -80

Solving for variable 'x'.

Reorder the terms:
80 + 80 + -19x + x2 = -80 + 80

Combine like terms: 80 + 80 = 160
160 + -19x + x2 = -80 + 80

Combine like terms: -80 + 80 = 0
160 + -19x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-160' to each side of the equation.
160 + -19x + -160 + x2 = 0 + -160

Reorder the terms:
160 + -160 + -19x + x2 = 0 + -160

Combine like terms: 160 + -160 = 0
0 + -19x + x2 = 0 + -160
-19x + x2 = 0 + -160

Combine like terms: 0 + -160 = -160
-19x + x2 = -160

The x term is -19x.  Take half its coefficient (-9.5).
Square it (90.25) and add it to both sides.

Add '90.25' to each side of the equation.
-19x + 90.25 + x2 = -160 + 90.25

Reorder the terms:
90.25 + -19x + x2 = -160 + 90.25

Combine like terms: -160 + 90.25 = -69.75
90.25 + -19x + x2 = -69.75

Factor a perfect square on the left side:
(x + -9.5)(x + -9.5) = -69.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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